Continuity of the input response for p < ∞ (Proposition 1.3) #
Proposition 1.3 (prop:finite-p-solution-continuous). Assume p ∈ [1, ∞).
For all u ∈ L^p(ℝ₊; U), t ↦ Φ_t u is continuous on ℝ₊.
The paper refers to [Weiss 1989, Proposition 2.3] and does not write out a proof.
We formalize the classical argument, which uses p < ∞ twice:
‖u‖_{L^p(0, t)} → 0ast → 0(ALCS.tendsto_norm_truncate). With causality and monotonicity ofκ, this givesΦ_t u → 0ast → 0⁺(ALCS.tendsto_Phi_zero).- Right continuity at
τ ≥ 0then follows from the composition propertyΦ_{τ+h} u = T_h Φ_τ u + Φ_h u(τ + ·)(ALCS.tendsto_Phi_right). - Left continuity at
τ > 0usesu = u ⋄_h u(h + ·), which givesΦ_τ u - Φ_{τ-h} u = T_{τ-h} Φ_h u + Φ_{τ-h} (u(h + ·) - u), and the continuity of translations inL^p(ALCS.tendsto_norm_shiftLeft_sub); seeALCS.tendsto_Phi_left.
The main statement is ALCS.continuousOn_Phi_of_ne_top.
Step 1: for p < ∞, Φ t u → 0 as t → 0⁺.
For t ∈ [0, 1], ‖Φ_t u‖ = ‖Φ_t (u ⋄_t 0)‖ ≤ ‖Φ_1‖ ‖u‖_{L^p(0, t)}.
Step 2 (right continuity): for p < ∞ and τ ≥ 0, Φ (τ + h) u → Φ τ u as h → 0⁺,
since Φ (τ + h) u = T h (Φ τ u) + Φ h u(τ + ·).
Step 3 (left continuity): for p < ∞ and τ > 0, Φ (τ - h) u → Φ τ u as h → 0⁺.
With u_h := u (h + ·), one has u = u ⋄_h u_h, hence
Φ τ u - Φ (τ - h) u = T (τ - h) (Φ h u) + Φ (τ - h) (u_h - u), so that
‖Φ τ u - Φ (τ - h) u‖ ≤ K ‖Φ h u‖ + ‖Φ τ‖ ‖u_h - u‖, where K bounds ‖T s‖ on [0, τ].
Proposition 1.3 (prop:finite-p-solution-continuous).
For p ∈ [1, ∞) and every input u ∈ L^p(ℝ₊; U), the map t ↦ Φ t u is continuous
on ℝ₊ = [0, ∞).