A suitable weak solution that is smooth on the unit cylinder is a classical solution #
Testing the weak momentum equation with ψ eₖ isolates its k-th component; integrating by
parts back (in time, in space, and twice for the viscous term through the weak-gradient pairing
identity) shows that the classical momentum residual integrates to zero against every test
function supported in the cylinder, so it vanishes there. Together with the pointwise divergence
equation this gives IsClassicalSolutionOn u p f unitCylinder, the passage from the weak to the
classical equations used in the proof of lem:aniso:annulus.
Testing with ψ eₖ collapses the weak momentum integrand to its k-th component.
A function continuous on the unit cylinder times a spatial partial of a test function supported in the cylinder is integrable.
A function continuous on the unit cylinder times the time partial of a test function supported in the cylinder is integrable.
A function continuous on the unit cylinder times a test function supported in the cylinder is integrable.
The product rule for a spatial partial at a point of the unit cylinder.
The convective term: ∫ u_k u_j ∂ⱼψ = -∫ (∂ⱼu_k u_j + u_k ∂ⱼu_j) ψ.
The viscous term: ∫ Du_{kj} ∂ⱼψ = -∫ ∂ⱼ∂ⱼu_k ψ.
The time partial of a smooth function vanishes off its topological support.
The weak momentum equation tested with ψ eₖ, as a whole-space integral of the collapsed
integrand.
The classical momentum residual of a suitable weak solution smooth on the unit cylinder integrates to zero against every test function supported in the cylinder.
A suitable weak solution on the unit cylinder whose velocity, pressure and force are smooth there is a classical solution there.