Newman's theorem, step 2: the integrality conditions ([Nw §3]) #
With g = κ·S, S = [[α, β/h], [hγ, δ]] and e = αδ − βγ (so κ²e = 1), conjugation by g is
Φ(M) = S M adj(S) / e. InL N M says that M is an integer matrix with N ∣ M₁₀ and ε ∣ M₁₁ − M₀₀
(ε = gcd(N, 24)); it holds on Γ₀(N) (units mod divisors of 24 square to 1) and is closed under
integer combinations. Applying Φ to E₁₂ = T − 1, NE₂₁ = U − 1, NE₂₂ = N − (TU − T − U + 1) and
(t − x)E₂₂ = γ − x − yE₁₂ − NE₂₁ (γ = [[x, y], [N, t]] ∈ Γ₀(N)) gives integer divisibilities.
The Γ₀(N) lattice, with parameter gcd(N, 24).
Equations
Instances For
theorem
CongruenceNormalizers.InL.of_mem
{N : ℕ}
{Y : Matrix.SpecialLinearGroup (Fin 2) ℝ}
(hY : Y ∈ Gamma0R N)
:
InL N ↑Y
Conjugation as a linear map #
Φ(M) = S M adj(S) / e.
Equations
- CongruenceNormalizers.Phi h α β γ δ M = (↑(α * δ - β * γ))⁻¹ • (CongruenceNormalizers.Smat h α β γ δ * M * (CongruenceNormalizers.Smat h α β γ δ).adjugate)