The successor step (Lemma S) #
Let N be closed over M and let ν satisfy J over M. There is a law ν' with
the marginals of ν on M, satisfying J over N, under which every vertex of
N \ M with infinitely many neighbours in M has trace energy at most C over them.
Proof. Force the signs of the set X of such vertices, giving the law
Λ = ν.map (forced X s). For each finite family of patterns over N, the key inequality
and the mixture lemma give a law with the marginals of Λ on M ∪ X meeting J for
those patterns. A limit along an ultrafilter finer than the filter of finite families
keeps the marginals on M ∪ X and meets J for every pattern over N.
For one finite family of patterns over N, the mixture lemma gives a law with the
marginals of the forced law on M ∪ X meeting J for the patterns of the family.
Lemma S.