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LeanPool.EscauriazaSereginSverak.LPS.ContinuationCutoff

Smooth time cutoffs at a slab endpoint #

A monotone smooth cutoff equal to one before b - 2ε and to zero after b - ε. Testing a weak formulation against such cutoffs exhibits the boundary term at the slab endpoint (lem:lps-continuation).

noncomputable def ESS.lpsCutoffRight (b ε t : ℝ) :

The smooth cutoff 1 on (-∞, b - 2ε] and 0 on [b - ε, ∞).

Equations
Instances For
    theorem ESS.lpsCutoffRight_eq_one {b ε t : ℝ} (hε : 0 < ε) (ht : t ≤ b - 2 * ε) :
    lpsCutoffRight b ε t = 1
    theorem ESS.lpsCutoffRight_eq_zero {b ε t : ℝ} (hε : 0 < ε) (ht : b - ε ≤ t) :
    lpsCutoffRight b ε t = 0
    theorem ESS.lpsCutoffRight_antitone {b ε : ℝ} (hε : 0 < ε) :
    theorem ESS.deriv_lpsCutoffRight_nonpos {b ε : ℝ} (hε : 0 < ε) (t : ℝ) :
    theorem ESS.deriv_lpsCutoffRight_eq_zero_of_le {b ε t : ℝ} (hε : 0 < ε) (ht : t < b - 2 * ε) :
    theorem ESS.deriv_lpsCutoffRight_eq_zero_of_ge {b ε t : ℝ} (hε : 0 < ε) (ht : b - ε < t) :

    Boundary term at the right end of a slab: if the cutoff-tested identity ∫ η_ε F₁ - ∫ η_ε' F₂ = 0 holds for all small ε and the time profile t ↦ ∫ F₂(·, t) tends to ℓ at b from the left, then ∫ F₁ = -ℓ (lem:lps-continuation).

    noncomputable def ESS.lpsCutoffLeft (a ε t : ℝ) :

    The smooth cutoff 0 on (-∞, a + ε] and 1 on [a + 2ε, ∞), obtained by reflecting the right-end cutoff.

    Equations
    Instances For
      theorem ESS.lpsCutoffLeft_eq_zero {a ε t : ℝ} (hε : 0 < ε) (ht : t ≤ a + ε) :
      lpsCutoffLeft a ε t = 0
      theorem ESS.lpsCutoffLeft_eq_one {a ε t : ℝ} (hε : 0 < ε) (ht : a + 2 * ε ≤ t) :
      lpsCutoffLeft a ε t = 1
      theorem ESS.deriv_lpsCutoffLeft_eq_zero_of_le {a ε t : ℝ} (hε : 0 < ε) (ht : t < a + ε) :
      deriv (lpsCutoffLeft a ε) t = 0
      theorem ESS.deriv_lpsCutoffLeft_eq_zero_of_ge {a ε t : ℝ} (hε : 0 < ε) (ht : a + 2 * ε < t) :
      deriv (lpsCutoffLeft a ε) t = 0

      Boundary term at the left end of a slab: if the cutoff-tested identity ∫ η_ε F₁ - ∫ η_ε' F₂ = 0 holds for all small ε with the left cutoffs and the time profile t ↦ ∫ F₂(·, t) tends to ℓ at a from the right, then ∫ F₁ = ℓ (lem:lps-continuation).