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LeanPool.EscauriazaSereginSverak.PartV.LocalSolutionDivFreeSlice

Heat-kernel pairings of a double-divergence-free slice #

At a fixed positive time r, the spatial derivative ∂_j Γ(·, r) of the heat kernel is paired with the translates y ↦ ∫ g_ij(w) ∂_i ψ(w + y) dw of a square-integrable tensor g against the derivatives of a test function ψ. Moving ∂_j from the kernel onto ψ and exchanging the integrals turns the pairing into -∫ Γ(y, r) ∑_ij ∫ g_ij(w) ∂_i ∂_j ψ(w + y) dw dy, which vanishes when ∑_ij ∂_i ∂_j g_ij = 0 in the sense of distributions. This is the fixed-time step in the proof that the forced heat response of a double-divergence-free tensor is divergence free (prop:pv-local-solution).

For integrable k, square-integrable g and continuous compactly supported φ, the function (y, w) ↦ k(y) g(w) φ(w + y) is integrable on Vec3 × Vec3: the inner integral is bounded by (‖g‖₂² + ‖φ‖₂²) / 2 uniformly in y.

At a positive time the spatial derivative of the heat kernel is integrable in space.

Integration by parts in space against the spatial derivative of the heat kernel at a positive time: ∫ ∂_j Γ(y, r) φ(w + y) dy = -∫ Γ(y, r) ∂_j φ(w + y) dy.

Moving the spatial derivative from the heat kernel onto the test function: for square-integrable g and a smooth compactly supported ψ, ∫ ∂_j Γ(y, r) ∫ g(w) ∂_i ψ(w + y) dw dy = -∫ Γ(y, r) ∫ g(w) ∂_i ∂_j ψ(w + y) dw dy.

theorem ESS.kernel_translate_pairing_sum_eq_zero {r : ℝ} (hr : 0 < r) {g : Fin 3 → Fin 3 → CKN.Foundation.Parabolic.Vec3 → ℝ} (hg : ∀ (i j : Fin 3), MeasureTheory.MemLp (g i j) 2 MeasureTheory.volume) (hdd : ∀ (φ : CKN.Foundation.Parabolic.Vec3 → ℝ), ContDiff ℝ (↑⊤) φ → HasCompactSupport φ → ∑ i : Fin 3, ∑ j : Fin 3, ∫ (y : CKN.Foundation.Parabolic.Vec3), g i j y * CKN.mixedSecond φ i j y = 0) {ψ : CKN.Foundation.Parabolic.Vec3 → ℝ} (hψ : ContDiff ℝ (↑⊤) ψ) (hψc : HasCompactSupport ψ) :

The heat-kernel pairing of a double-divergence-free square-integrable tensor vanishes: if ∑_ij ∫ g_ij ∂_i ∂_j φ = 0 for every smooth compactly supported φ, then ∑_ij ∫ ∂_j Γ(y, r) ∫ g_ij(w) ∂_i ψ(w + y) dw dy = 0.