f(2) = 2 ([I71, Lemma 5], the part we need) #
We prove (3.9), f(s) = f(4) + (F(3) + 3) log (3/(s-1)) + s - 4 on [2, 4], and f(2) = 2,
following Iwaniec: M = f + F satisfies M'(s) = -M(s-1)/(s-1) for s > 3 once it is extended
to [2, 3] by M(s) = 3 + F(3) - s + f(s) (MSieve). Then
Q(s) = (s-1) M(s) - ∫_{s-1}^s M has derivative 0 on (3, 4) ∪ (4, ∞), so it is constant on
[3, ∞), and it tends to 0 because M(s) = O(s e^{-s}). Evaluating Q(3) = 0 gives
f(4) + (F(3) + 3) log 3 = 4, i.e. f(s) = s - (F(3) + 3) log (s - 1) on [2, 4].
The value F(3) = 2e^γ - 3 is not needed; only F(3) ≥ 0 is used for the final inequality
1 - f(s)/s ≥ 3 log (s - 1) / s on [2, 4]. The rest of Lemma 5 (F(3) = 2e^γ - 3 via Buchstab's
function) is in IwaniecLinearSieve.EulerGamma.LemmaFive.
(3.9) #
Derivatives #
Derivative of u ↦ ∫_u^∞ k.
Iwaniec's M #
Iwaniec's M(s): f(s) + F(s) for s ≥ 3, extended by M(s) = 3 + F(3) - s + f(s) for
s ≤ 3 (which is -s M'(s+1) on [2, 3]).
Equations
- IwaniecLinearSieve.MSieve s = IwaniecLinearSieve.fSieve s + IwaniecLinearSieve.FSieve s + max (3 - s) 0
Instances For
The conserved quantity #
Q(s) = (s - 1) M(s) - ∫_{s-1}^s M.
Equations
- IwaniecLinearSieve.lemma5Q s = (s - 1) * IwaniecLinearSieve.MSieve s - ∫ (x : ℝ) in s - 1..s, IwaniecLinearSieve.MSieve x