Exact constants and finite constant extensions #
Let N / C be a field extension whose exact constant field is C, meaning
that no element of N \ C is algebraic over C. If S / C is finite
Galois, then S and N are linearly disjoint over C. Consequently the
tensor product S ⊗[C] N is a field, and its degree over N is [S : C].
Mathlib's finite-Galois intersection criterion assumes both intermediate fields are finite over the base. The first theorem below proves the variant needed here: only the Galois field on the left must be finite. This is the algebraic foundation for the constant-extension twists in Stichtenoth, Proposition 5.2.8.
A finite Galois intermediate field is linearly disjoint from any other intermediate field having trivial intersection with it. Unlike Mathlib's finite intersection criterion, the field on the right need not be finite over the base.
Inside a common algebraic closure, a finite Galois constant extension and
a field with exact constant field C are linearly disjoint over C.
If C is the exact constant field of N, adjoining any finite Galois
extension S / C by tensor product produces a field.
The algebra structure on S ⊗[C] N induced by the copy of N in the
right tensor factor.
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Commuting the tensor factors identifies the constant extension with the
usual scalar extension of S from C to N.
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- One or more equations did not get rendered due to their size.