A010: ∫₀^{π/4} x² tan² x dx = -G + π²/16 - π³/192 + (π/4) log 2 #
On [0, π/4] the function H x = x² tan x + 2x log cos x - x³/3 has derivative
x² tan² x + 2 log cos x, because 1/cos² x - 1 = tan² x. Hence
∫₀^{π/4} x² tan² x dx = H(π/4) - H(0) - 2 ∫₀^{π/4} log cos x dx, and A006 gives the last
integral.