Bienaymé trees: weights, the branching property and forests #
Source lines 679–704 (Section 2.1) of the paper. For an arbitrary offspring law μ (a PMF
on ℕ, no criticality assumed) we prove:
weight_node:𝐏_μ(node [t_1,…,t_k]) = μ_k ∏ 𝐏_μ(t_i), andbienayme_apply_singleton: the Bienaymé measure gives each finite tree its weight∏_{u∈T} μ_{k_u(T)};bienayme_apply: the measure of any set of trees is the sum of the weights;- the branching property (
bienayme_children_eq,bienayme_rootDegree_eq_children_mem,bienayme_node_ofFn_mem): given the root degreek, thekchild subtrees are independentμ-Bienaymé trees; - the forest product formulas
tsum_forest_fin,tsum_forest_list, and the law of the sizebienayme_vertexCount_succin terms of forest sizesforestSizeWeight; bienayme_univ_le_one: the total weight of the finite trees is at most one, sobienayme μis a finite measure. That it equals one for criticalμwithμ 1 ≠ 1is proved inPoissonDeclumping.Bienayme.Normalization.
Tree combinatorics #
The number of vertices is one plus the total size of the root's child trees.
Finite plane trees are in bijection with pairs (k, (T_0, …, T_{k-1})): the root degree
and the ordered tuple of child trees.
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Weights and the Bienaymé measure #
General branching decomposition: if membership of node [T_0, …, T_{k-1}] in s means
k ∈ D and T_i ∈ A k i for all i, then 𝐏_μ(s) = ∑_{k ∈ D} μ_k ∏_i 𝐏_μ(A k i).
Branching property #
The law of the root's children: 𝐏_μ(children = [t_1, …, t_k]) = μ_k ∏_i 𝐏_μ(t_i).
Forests #
Total weight of the k-tuples of trees with n vertices in total: the probability that
a forest of k independent μ-Bienaymé trees has n vertices.
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- One or more equations did not get rendered due to their size.
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Total mass at most one #
Trees of height at most h (an auxiliary truncation).