Scott's intransitive-indifference problem #
The definitions reproduce conditions (1_P)--(3_P) in §2. The elementary
direction of Theorem 2.1 is recorded here; the converse is supplied by the
finite linear-inequality engine.
A strict preference relation is represented with discrimination threshold 1.
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Scott 1964, condition (1_P).
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- Scott1964.MeasurementStructures.PrefIrrefl P = ∀ (x : A), ¬P x x
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Scott 1964, condition (2_P).
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- Scott1964.MeasurementStructures.PrefQuadA P = ∀ (x y z w : A), P x y → P z w → P x w ∨ P z y
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Scott 1964, condition (3_P).
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- Scott1964.MeasurementStructures.PrefQuadB P = ∀ (x y z w : A), P x y → P z x → P w y ∨ P z w
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Realization with a strict margin above the conventional unit threshold.
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Scott's stronger conclusion following Theorem 2.1: the same unit threshold may be taken strict on every preferred pair.
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Scott 1964, Theorem 2.1 (intransitive indifference).
The nonemptiness assumption in the source is unnecessary here.
The converse uses the direct finite Scott--Suppes construction: quotient by
substitutability, order the quotient by the weak order ScottWeakOrder, and
represent its nested lower sections by a recursively constructed sequence.
Any positive discrimination threshold can be changed to 1 by a change
of units, as noted immediately before §1.
Rescaling any unit-threshold realization produces an arbitrary positive margin above the unit threshold.
On a finite set the boundary can be avoided altogether, as Scott notes after Theorem 2.1: preferred pairs lie strictly beyond the same unit threshold.