A mod-five quotient of Borisov's two-HNN group #
Both stable letters act on the free product C₅ * C₅ by inverting each
free factor. Since 4 = -1 (mod 5), the four power-conjugation relations of
Gamma3 hold in the resulting semidirect product. This quotient is useful
because every positive displayed rule contributes two nontrivial alternating
free-product syllables.
The cyclic group of order five, written multiplicatively.
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The free product of the two order-five base factors.
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The standard generator of the multiplicative order-five cyclic group.
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The generator of the second order-five factor, representing e.
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The inversion homomorphism of the abelian order-five cyclic group.
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The homomorphism inverting both cyclic free-product factors.
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The involutive automorphism inverting both cyclic free-product factors.
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The infinite cyclic action generated by factorwise inversion. Using an
infinite cyclic acting group avoids any quotient bookkeeping; the action
still has period two because invertFactors is involutive.
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The semidirect product of the order-five free product by simultaneous inversion.
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The inclusion of the order-five free product into the semidirect product.
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The semidirect-product stable generator implementing simultaneous inversion.
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The free-group homomorphism reducing both base generators modulo five.
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The base-group homomorphism into the mod-five semidirect-product quotient.
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Extend the base quotient map across the first HNN extension.
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Extend the quotient map across the second HNN extension.
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