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LeanPool.Superdiffusion.Algsuperdiff.Section4.Provider.Annular.LatticeCover

LatticeCover #

Ported from scottnarmstrong/Superdiffusion at 7f20476385d4af418f110303085ad0740c9eba46. Module imports, support namespace and local option directives adapted for Lean Pool.

The scale-k lattice tiling of cu_m, and the shell gauge it dominates #

ABK26, Section 4.1, the two Step-2 budget displays. Both perform the same unremarked move: a shell norm read on the annulus cube z + cu_n (with z a scale-n lattice point) is replaced by the maximum of the W^{2,infinity} shell gauge over the scale-k lattice cubes of cu_m -- the very family the good event Support.eventG1's second condition, and the frozen clause-(i) fourth term, are written with.

Support.GaugeBridge's scope note records that this "lattice-max enlargement" is NOT proved there (only the same-centre cube-scale comparison is).

Recorded here, because it fixes the route taken below: the naive reading -- first enlarge z + cu_n to z + cu_k at the same centre by Support.shellW1InfGradNorm_le_zpow_mul_of_le, then look for a scale-k lattice cube of cu_m containing the enlarged cube -- does NOT close. For k > n and z at the outer edge of the annulus the enlarged cube leaves cu_m: z = 3^n v with |z_i| <= (3^m - 3^n)/2 only gives |z_i| + 3^k/2 <= 3^m/2 + (3^k - 3^n)/2, which exceeds 3^m/2 as soon as k > n.

This module proves the move by the other route, which needs no enlargement:

Only the half-open tiling is exact, so a point of z + cu_n may land on a tile face, which the open-cube sup gauges of the shell layer do not see. The gap is closed by continuity: the frozen ShellField carries continuous first and second derivatives, so the sup over an open triadic cube already bounds the value at every point of its half-open closure (..._le_localCubeSecondDerivNorm_cubeSet and its two siblings).

Main results #

References #

Part A -- the half-open tiling of cu_m by scale-k lattice cubes #

The scale-k lattice cubes tile cu_m.

Every point of the open cube cu_m lies in the half-open realization cubeSet of exactly one scale-k lattice cube 3^k w + cu_k with w ∈ 3^k Z^d ∩ cu_m -- the index family of the good event's second condition and of the frozen clause-(i) fourth term. The index is the coordinatewise rounding w_i = floor(x_i 3^{-k} + 1/2), and it stays inside the balanced box because 3^{m-k} is odd.

Part B -- the open-cube sup gauges see the half-open closure #

The second-derivative gauge of a shell dominates the exact induced norm at every point of the half-open triadic cube, not only the open one: the frozen shell carrier stores a continuous second derivative.

The layer-sum triangle inequality at the value gauge, the L^infinity analogue of Support.shellW1InfGradNorm_translate_sum_le.

Part C -- the annulus cube stays inside the observation cube #

z + cu_n is contained in cu_m for every scale-n lattice point z of cu_m and every n <= m. The containment is in the open cube on both sides: z is a lattice point, so |z_i| <= (3^m - 3^n)/2 exactly.

Part D -- the lattice-max enlargement at the two shell gauges #

DisplaySlots.shellW2InfLatticeMax, read at an abstract shell field: the maximum of the W^{2,infinity} gauge over 3^k Z^d ∩ cu_m.

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Instances For

    The lattice-max enlargement of the W^{1,infinity} shell gauge: the gauge of a shell on the annulus cube z + cu_n is at most max(1, 3^{k-n}) times the maximum of its W^{2,infinity} gauge over the scale-k lattice cubes of cu_m, for every k <= m.