OneStepConsumerLegBudget #
Ported from scottnarmstrong/Superdiffusion at 7f20476385d4af418f110303085ad0740c9eba46. Module imports, support namespace and local option directives adapted for Lean Pool.
The consumer-side budget of the general clause's right-hand side #
The general clause consumed here carries ‖u − h‖_{L²(W')} in its first
bracket leg and s^{-6} on legs 4 and 5, in place of the plain mean-subtracted
norm ‖u − (u)_{W'}‖_{L²(W')} and the exponent s^{-9/2}.
At the excess-decay application (OneStepConditional. excessDecay_oneStep_of_harmonicApprox, instance n := n-2,
x := wellPlacedCentre x m (n-2)) the clause's right-hand side is received as
the abstract B, and the excess-decay display multiplies B.toReal by
triangleRemainderConst d Csch k * (3^{-n} * √((3^2)^d)). So every leg must
survive multiplication by 3^{-n} into the excess-decay conclusion shape. This
module proves what does survive; what does not is treated in
OneStepConsumerRefutation.
What is proved here #
- §1 The
s^{-9/2} → s^{-6}exponent move is a weakening, and it is invisible to the proved chain.rpow_neg_nine_halves_le_rpow_neg_six: for0 < s ≤ 1,s^{-9/2} ≤ s^{-6}, so thes^{-6}right-hand side dominates thes^{-9/2}one leg for leg. At the sole eventual pins = 1/4(Regularity.MinimalScaleShift.stepOneS) both exponents are numerals,4^{9/2} = 512and4^6 = 4096— a factor8, absorbed intoC(d,c⋆). - §2 The good-event collapse.
rpow_neg_four_mul_goodEventCap_le_rpow_neg_six: the clause's flux prefactors^{-4}against the proved cap𝓔·1_𝒢 ≤ C s δ^{1/2}(OneStepGoodScales. ae_errorRepresentative_le_goodEventDeltaSlot) collapses tos^{-3}δ^{1/2}, which is below the clause's owns^{-6}for every0 < s ≤ 1,δ ≤ 1. - §3 The conditional absorption lemma — the exact shape the
B-expansion needs for the new first leg, on the boundary branch:dataSubtracted_leg_absorbed_of_flatGradientBound. ThehGuslot — a bound on the flat window gradient∑ᵢ ‖∂ᵢu‖_{L²(W')}— has no producer and is carried as an open hypothesis. - §4 The
∇hhalf is free.gradH_half_eq_leg5_contribution: the datum half of §3's bound is equal to9·C_cap·C_pointimes the clause's own fifth leg after the excess-decay3^{-n}, at the exponents^{-6}. So the datum half of the new leg costs nothing beyond ad-constant.
1. The s^{-9/2} → s^{-6} exponent move #
The exponent move weakens the clause. For 0 < s ≤ 1 the exponent
s^{-6} dominates s^{-9/2}, so on legs 4 and 5 the right-hand side carrying
s^{-6} is at least the one carrying s^{-9/2} — the consumer receives a
weaker bound, and absorbing it is absorbing the larger of the two.