StepSevenCaccVolume #
Ported from scottnarmstrong/Superdiffusion at 7f20476385d4af418f110303085ad0740c9eba46. Module imports, support namespace and local option directives adapted for Lean Pool.
t.regularity Step 7c, the volume factor #
The target #
ABK26 t.regularity Step 7c, the sentence
Since
(z + □_n) ∩ □_m ⊆ U_{n'-2}, passing to the smaller set costs a volume factor3^{(d/2)(n'-n)} ≤ 3^{(d/2)(|𝓑|+6)}. Bye.bad.scale.proportion.bound, this is at mostC 3^{(1/4)(1-α)(m-n)}.
Two independent halves, both proved here unconditionally.
Half one — what "costs a volume factor" means #
The manuscript asserts the factor by inspection. The decomposition it hides: the factor is the square root of the ratio of the two volumes, and the ratio is bounded by combining
- the inclusion
(z + □_{n+1}) ∩ □_m ⊆ U_{n'-2}(the step's own stated hypothesis, coming from the selection and the window geometry), and - the volume lower bound
3^{dn} ≤ |(z + □_{n+1}) ∩ □_m|against the upper bound|U_{n'-2}| ≤ |□_{n'}| = 3^{dn'}.
normalizedSqrt_le_volumeRatio_mul is that decomposition at the level of the
volume-normalized L² masses: for S ⊆ T with 0 < |S|,
( |S|⁻¹ ∫_S f )^{1/2} ≤ ( |T| / |S| )^{1/2} · ( |T|⁻¹ ∫_T f )^{1/2} ,
which is an identity plus monotonicity of the integral, no analysis. It is
stated on the scalars IS ≤ IT and volS, volT so that it composes with any
rendering of the two masses (: the ABK26 field is 𝐚_L = ν I + 𝐤 with 𝐤
antisymmetric, so ν^{1/2}‖∇u‖_{L²} IS the symmetric coefficient energy — the
left-hand side of e.gradient.with.shom is a coefficient-energy mass and the
comparison above is exactly what it needs).
Half two — the budget arithmetic #
stepSevenVolumeExponent_le_of_gap is the tex's second sentence, in full:
(d/2)(n'-n) ≤ (d/2)(|𝓑| + G) (the selection's gap)
≤ (d/2)·δ·((m-n) + 1) + (d/2)G (e.bad.scale.proportion.bound)
≤ (d/2)·C₁⁻¹(1-α)((m-n) + 1) + (d/2)G (δ ≤ C₁⁻¹(1-α))
≤ (1/4)(1-α)(m-n) + 1/4 + (d/2)G (C₁ ≥ 2d+2, and 1-α ≤ 1)
At G = 6 — the printed gap max{n'-n, m-m'} ≤ |𝓑| + 6 — the constant is
3^{3d + 1/4}. strengthened the lower gap to the sharp n'-n ≤ |𝓑| + 3, and
at G = 3 the constant improves to 3^{3d/2 + 1/4}. Both are delivered.
References #
- ABK26,
t.regularityStep 7c. - ABK26,
e.bad.scale.proportion.bound.
1. Half one — the volume-ratio cost of passing to a smaller set #
** (b), the scalar core.** If the mass IS carried by the smaller set is at
most the mass IT carried by the larger one, then the volume-normalized
square roots compare at the cost of the square root of the volume ratio:
√(IS / volS) ≤ √(volT / volS) · √(IT / volT) .
No hypothesis beyond positivity of the two volumes and monotonicity of the mass.
The volume ratio at the two triadic scales. With 3^{dn} ≤ |S| (the
tex-implicit lower bound on the truncated window (z + □_{n+1}) ∩ □_m) and
|T| ≤ 3^{dn'} (the trivial upper bound on U_{n'-2} ⊆ z + □_{n'}), the
square root of the volume ratio is the printed factor 3^{(d/2)(n'-n)}.
2. Half two — the budget arithmetic #
(d/2)·C₁⁻¹ ≤ 1/4's floor C₁ ≥ 2d + 2. This is the only place the
C₁-largeness of the volume factor is used, and it is the +2 (not the naive
C₁ ≥ 2d) that makes it go through with room to spare.
The volume exponent, bounded by the budget (second sentence).
At a gap n' - n ≤ |𝓑| + G, the budget |𝓑| ≤ δ((m-n)+1), the parameter
choice δ ≤ C₁⁻¹(1-α)'s floor C₁ ≥ 2d + 2:
(d/2)(n' - n) ≤ (d/2)·G + 1/4 + (1/4)(1-α)(m-n) .
The +1/4 is the budget's own +1 (δ((m-n)+1) rather than δ(m-n))
weighted by (1/4)(1-α) ≤ 1/4.
The volume factor itself, at the printed gap n' - n ≤ |𝓑| + 6:
3^{(d/2)(n'-n)} ≤ 3^{3d + 1/4} · 3^{(1/4)(1-α)(m-n)}, i.e. the
tex's C 3^{(1/4)(1-α)(m-n)} with the constant C = C(d) = 3^{3d + 1/4} made
explicit.