StepSixBoundaryIterationC1 #
Ported from scottnarmstrong/Superdiffusion at 7f20476385d4af418f110303085ad0740c9eba46. Module imports, support namespace and local option directives adapted for Lean Pool.
1. The three constants of the boundary Step-4 output #
2. The boundary dataH, and its two Step-6 legs #
The boundary ∇h leg of e.sum.delta.j.bound —'s α-free grouping, with
NO ε-free flat summand:
dataH_∂ = C_ah·3^{m/2}(1+C_gag)K_h/(1-3^{-1/2}) + S_ε·(2 C_bd 3^{m/2} K_h) .
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3. e.oscillation.iteration.result on the boundary branch #
e.oscillation.iteration.result printed lattice centre, hstep4 GONE.
The interior endpoint's sibling off's boundary Step-4 slot: no interiority
gate, the contraction over k+1 scales, and the nonzero boundary dataH_∂.
4. The boundary Step 6, in the chain's hosc shape #
The printed boundary ∇h datum leg — α-free, γ-free, δ-free, and a
multiple of 3^{m/2} K_h:
dataH^print_∂ = C_ah·3^{m/2}(1+C_gag)K_h/(1-3^{-1/2})
+ (4/log 3)·(2 C_bd 3^{m/2} K_h) .
The absolute constant 4/log 3 is the price's ε-funded absorption; no
(1-α)^{-1} occurs, because's boundary δ carries no ε-free flat summand.
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t.regularity Step 6 on the boundary branch, in the Step-7 chain's own
hosc slot.
The ε-funded absorption at ind := 1, re-grouped so the produced data leg is
a single dataG + dataH^print_∂ bracket at one constant C + C² — exactly the
shape StepSevenCaccFinalChain's hosc reads (there at H = 0).
e.oscillation.Holder.bound printed lattice centre.
edFinal_oscillationIterationResult_boundaryC1 composed with the boundary
Step 6: the interior endpoint's shape with the same dataG and a nonzero
printed dataH^print_∂.
5. The two boundary funding floors #
The boundary Step-4 δ-cap, from a pure C₁-floor.
stepFourDecay_boundary_pinned's δ-cap δ ≤ 64C^{-2}s^6 is met by every δ = C₁^{-1}(1-α) with α ≥ 0 once C₁ ≥ 64C², because s = 1/4 makes the cap
exactly (64C²)^{-1}.
The boundary Step-4 smallness gate, from a pure C₁-floor.
RootClauseBFinalFunding.edFunding_of_c1_floor's sibling for the boundary lane:
the gate
C_{eps,gen}(d,C_s,C,k)·C_cap·s^{-3}·√δ ≤ ½·3^{-(k+1)/4}
holds at every δ = C₁^{-1}(1-α) with α ≥ 0 once C₁ clears the explicit
floor (2·C_{eps,gen}·C_cap·s^{-3}·3^{(k+1)/4})². No division and no
positivity of the constant is needed — the argument is √δ ≤ (√C₁)^{-1} and
one cross multiplication.
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