Bisection for a monotone zero and normalized clearing #
Bisection evaluates excess supply at the midpoint of a bracket and keeps the half containing
the zero. Hajek and Livesay (2019) discuss stability of best-response fixed points in mean field
games. Here, a decreasing inverse-demand map composed with an increasing supply map can reverse
order, so raw iteration r ↦ r_d(K_s(r)) may oscillate. This file certifies bisection.
The abstract statement #
bisect f a b n is the bracket after n steps. If f is STRICTLY MONOTONE on [a, b] and
vanishes at r ∈ [a, b], then every bracket contains r (bisect_mem_of_strictMonoOn), the
width halves each step (bisect_width), and the endpoints converge to r
(tendsto_bisect_fst). No continuity and no sign condition at the ends are used: strict
monotonicity alone decides which half the zero is in. The midpoint after n steps is within
(b - a)/2^(n+1) of r (abs_bisect_mid_sub_le).
The instance #
For the capped log-household calibration, stationary mean assets are monotone in the rate
under the stated hypotheses, and the prescribed normalized demand is strictly decreasing.
Thus normalized excess supply is strictly increasing. Given a stationary distribution and a
rate solving that explicit normalized clearing equation, aiyagari1994_log_bisection proves
that bisection brackets the rate and converges to it. Existence of such a solution is an input.
Normalized clearing scope #
The economic endpoints use the prescribed equation
aggregateCapital μ = normalisedDemand (9/25) (2/25) r, where the right side is
(9/25) / ((1 - 9/25) * (r + 2/25)). This is a unit-wage normalized clearing problem.
The household earnings scale is arbitrary; no mean-one endowment condition or bridge from
these units and the fixed asset cap to full competitive market clearing is established here.
The uniqueness and bisection claims concern this explicit normalized equation.
Bisection on the line #
One bisection step on a bracket (a, b): if f ≤ 0 at the midpoint the zero of an
increasing f is to the right, so keep (mid, b); otherwise keep (a, mid).
Equations
Instances For
Every bracket contains the zero of a strictly increasing function, and stays inside the initial bracket.
The bracket width tends to zero.
The left endpoints converge to the zero.
The right endpoints converge to the zero.
Monotone supply minus strictly decreasing demand is strictly increasing.
The log Aiyagari instance #
Excess supply along a selection of stationary distributions: capital supplied under
ν r minus capital demanded at r.
Equations
- P.excessSupply ν D r = P.aggregateCapital (ν r) - D r
Instances For
The two facts about a selection that the bisection needs, from one inequality on the cap:
supply along it is monotone, and it is the ONLY stationary distribution at each rate. The
constants are chosen as in log_equilibriumRate_unique_of_cap.
Bisection on excess supply brackets and converges to the equilibrium rate of the log economy, along any selection of stationary distributions.
Bisection for normalized clearing with the Aiyagari log calibration. On any
[rlo, rhi] ⊂ (-δ, λ) with the cap clearing (48/25)·maxIncome/(1 - (24/25)(1+rhi)), and along
any selection of stationary distributions, the bisection on excess supply brackets the
equilibrium rate at every step, its midpoint is within (rhi - rlo)/2^(n+1) after n steps,
and its endpoints converge to the rate.